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HSC Chemistry
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Module 5: Equilibrium and Acid Reactions5.1 Static and Dynamic Equilibrium5 Topics
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5.2 Factors that Affect Equilibrium2 Topics
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5.3 Calculating the Equilibrium Constant2 Topics
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5.4 Solution Equilibria
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Module 6: Acid/Base Reactions6.1 Properties of Acids and Bases7 Topics
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6.2 Using Brønsted–Lowry Theory2 Topics
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6.3 Quantitative Analysis1 Topic
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Module 7: Organic Chemistry7.1 Nomenclature2 Topics
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7.2 Hydrocarbons2 Topics
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7.3 Products of Reactions Involving Hydrocarbons
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7.4 Alcohols1 Topic
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7.5 Reactions of Organic Acids and Bases
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7.6 Polymers2 Topics
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Module 8: Applying Chemical Ideas8.1 Analysis of Inorganic Substances3 Topics
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8.2 Analysis of Organic Substances
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8.3 Chemical Synthesis and Design
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Working ScientificallyWorking Scientifically Overview1 Topic
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EduKits Education
Lesson 1, Topic 5
In Progress
Entropy and Enthalpy in Non-equilibrium Systems
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- Enthalpy (H) is the heat content of a system.
- Entropy (S) is a measure of the distribution of available energy, but is also a measure of disorder.
- These determine whether a reaction is:
- Spontaneous – Proceeds without needing a continual input of energy from an external source.
- Non-spontaneous – Requires a continual input of energy from an external source.
The Gibbs free energy formula predicts the spontaneity of a reaction.
\Delta G\degree = \Delta H\degree - T\Delta S\degree
- If [katex]\Delta G\degree > 0[/katex], reaction is non-spontaneous.
- If [katex]\Delta G\degree = 0[/katex], system is at equilibrium.
- If [katex]\Delta G\degree < 0[/katex], reaction is spontaneous.
Combustion
Consider the complete combustion of octane.
C_8H_{18 (l)} + \frac{25}2 O_{2 (g)} \rightarrow 8CO_{2 (g)} + 9H_2O_{(l)}
- Combustion is exothermic as it always releases heat, i.e. [katex]\Delta H\degree < 0[/katex]
- Entropy can either be positive or negative, depending on the number of moles of gas on each side of the reaction
- For octane, entropy decreases as there are fewer moles of gas resulting from the reaction, i.e. [katex]\Delta S \degree < 0[/katex]
However, [katex]\Delta G\degree < 0[/katex] for all combustion reactions, regardless of temperature of molar ratios, as enthalpy is always extremely negative. Therefore, combustion is a spontaneous reaction.
Photosynthesis
6CO_{2 (g)} + 6H_2O_{(l)} \rightarrow C_6H_{12}O_{6 (aq)} + 6O_{2 (g)}
- Photosynthesis is endothermic, absorbing energy from the sun, i.e. [katex]\Delta H\degree > 0[/katex]
- Entropy decreases as there are 6 moles of gas on each side but more overall particles on the reactants size, i.e. [katex]\Delta S\degree < 0[/katex]
For photosynthesis, [katex]\Delta G\degree > 0[/katex] so it is a non-spontaneous reaction which requires a constant input of energy to proceed.